Takshila Learning - Online Tutorials

10th Class Maths NCERT Online Solutions- Real Numbers Few Solved examples for  Maths Class 10th  students NCERT Maths Solutions Class 10 Eg 1 -A number, when divided by 53, gives 34 as quotient and 21 as remainder. Find the number. Soln -Using Euclid’s division algorithm we have Dividend= (divisor*quotient) +remainder = (53*34) +21 = (1802+21) =1823 NCERT Maths Solutions Class 10 Eg 2 –  Show that one and only one out of n, (n+1) and (n+2) is divisible by 3, where n is any positive integer? Sol – let’s assume that on dividing  n  by 3,  q  will be the quotient and  r  will be the remainder. N=3q+r where r=0, 1 or 2 N=3q or n =3q+1 or n 3q+2 Case 1 – if n=3q, then n is clearly divisible by 3. Case 2 – if n= (3q+1), then (n+2)=3q+3=3(q+1),which is clearly divisible by 3,hence (n+2) is divisible by 3 Case 3 – if n= (3q+2), then (n+1)=(3q+3)=3(q+1),which is clearly divisible by 3,hence (n+1) is divisible by 3 Hence only one out of 3 is divisible by 3.