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Numbers and place value Class 3 Maths Worksheet for Practice

Numbers and place value Class 3 Maths Worksheet for Practice Write the number name for given numeral: 45 = …………………………………………………………………………………………………………………………….. 123= …………………………………………………………………………………………………………………………….. 13= ……………………………………………………………………………………………………………………………… 3000= ………………………………………………………………………………………………………………………………. 657= ………………………………………………………………………………………………………………… Fill in the blanks: 470 means …………. hundreds, ………. tens, ……… one 524 means …………. Hundreds, ……….. tens, ………… ones 1325 means …………. thousands, …………. hundreds, …………. tens, ………… ones 2435 means …………. Thousands,………….. hundred, ………… tens, ………… one Continue complete worksheet and download click Numbers and place  For details kindly visit www.takshilalearning.com

General Awareness for Bank PO & Clerk – Static Awareness of UTTAR PRADESH (UP)

General Awareness for Bank PO & Clerk – Static Awareness of  UTTAR PRADESH (UP) UTTAR PRADESH (UP) : Static Awareness forms the most important part of General Awareness section in mains examination. Earlier questions from banking section were mainly asked from this section but the trend has now changed & questions from Static Awareness portion is also asked in bulk. Let us look at the Static Awareness of Uttar Pradesh : Uttar Pradesh is also known as the  Sugar Bowl of India. Uttar Pradesh was established on  1 st  April 1937 . Earlier, its name was United Provinces. In 1950, it was renamed as Uttar Pradesh. Capital city:  Lucknow Chief Minister:  Yogi Adityanath Governor:  Ram Naik Number of Districts:  75(Highest Number of Districts among 29 states) Uttar Pradesh shares its border with  5 states & 1 UT  i.e., Bihar, Rajasthan, Delhi, Haryana, Uttarakhand, and Madhya Pradesh. International Border:  Nepal High Court:  Allahabad High Court Utta

NCERT Chemistry Class 11 Notes Heisenberg Uncertainty Principle

NCERT Chemistry Class 11 Notes Heisenberg Uncertainty Principle Class 11 Chemistry Notes : According to the Heisenberg’s uncertainty rule, it is not possible to know exactly both the position and the momentum of an electron. Thus, the  certainty  of determination of one property leads to  uncertainty of  determination of the other. The uncertainty in the measurement of position, ∆x, and uncertainty of determination of momentum, ∆p are related by Heisenberg’s relationship as- (∆x) X (∆p) ≥ h/4π Where h is Planck’s constant. If ∆x is very small, i.e., the position of the electron is known more or less exactly, ∆p would be large, i.e. uncertainty of momentum will be large or vice- versa. On the basis of the concept of probability, it is possible to state or predict the probability or relative chance of finding an electron of a particular energy in a given region of space at a given time. The volume in space around the nucleus of the atom, in which there is the maximum pro

CBSE class 12th biology notes Population and Population Growth

CBSE class 12th biology notes Population and Population Growth There are four variables/ causes that govern the population growth/population size: Birth rate(Natality):  It is defined as a number of births per 1000 individuals in one year. Death rate (Mortality):  It is defined as a number of death per 1000 individuals per year. Immigration:  Entry of individuals in a given population. Emigration:  Exit of individuals from a given population. A population gains individuals by birth and immigration and loses them by deaths and emigration. Thus, population change = (Births + Immigration) – (Deaths + Emigration) Effect of Age Distribution on Population growth In many organisms, the generations overlap. It is shown, from a theoretical point of view, that competition between the different ages classes in such organisms will have important population dynamics consequences. Strong competition between age classes can be either a stabilizing or destabilizing force depending

Class 8 Maths Chapter 16 Visualizing Shapes – Prism – Part ii

Class 8 Maths Chapter 16 Visualizing Shapes – Prism – Part ii 8th Class maths:- Triangular prism: –  If the base of a prism is triangles, a prism is called a triangular prism. A triangular prism has i. 6 vertices and 9 edges ii. 2 triangular bases iii. 3 rectangular lateral faces Right Triangular prism: – A triangular prism whose lateral edges are perpendicular to its bases is called a right triangular prism Watch animated videos for a better understanding of types of the prism, click here  Class 8th Maths  for demos. The prism is further classified on the basis of the number of sides in the bases. Rectangular prism  :-  It is also called cuboid or rectangular solid. It has 6 rectangular faces along with 8 vertices and 12 edges. Continue visit complete chapter click  Visualizing Shapes – Prism For more articles, demos, sample papers,  NCERT Maths solutions Class 8 , kindly visit our  8th Class Maths  Section

Online Notes Our Environment From Chapter 1 Social Science of Class 7

Online Notes Our Environment From Chapter 1 Social Science of Class 7 Natural Environment The natural environment consists of 4 layers-lithosphere, atmosphere, hydrosphere, and biosphere. The lithosphere-t he lithosphere is the outermost layer of the earth. It is also called crust. The earth crust is made up of different types of rocks. The crustal blocks are of two types-Continental and oceanic blocks. The continental crust lies below the landmass varying 40 km to 100 km in thickness. The oceanic crust lies below the ocean and it is only about 6 km thick. Atmosphere -The atmosphere is the layer of air that surrounds the earth. Air is the mixture of gases like nitrogen 78%, oxygen 21% and rest 1% comprises of carbon dioxide and other gases. The layer is thicker at the land surface and thinner at higher levels. The atmosphere helps life to survive on the earth. Continue complete chapter click   Our Environment Class 7  Social Science For details click  www.takshilalea

CALENDARS General Awareness for bank exams | Calendar Questions and Answers

CALENDARS General Awareness for bank exams | Calendar Questions and Answers Ordinary Year: The year which is not a leap year is called an ordinary year. An ordinary year has 365 days. Leap Year: A leap year has 366 days. Every year divisible by 4 is a leap year, given that it is not a century year. Every 4 th  century is a leap year and no other century is a leap year. For eg: Each of the years 1944, 2008, 1680 etc. is a leap year. Each of the years 400, 800, 1200, 1600, 2000 etc. is a leap year. The concept  of Odd Days & how to calculate it: In an ordinary year, there are 365 days in a year that means 52 x 7 + 1, or 52 weeks and one day. This additional day is called an  odd day . The concept of odd days is very important from calendars point of view. How to Count Number of Odd Days: 1 ordinary year = 365 days = (52 weeks + 1 day.) So,  1 ordinary year has  1 odd day . 1 leap year = 366 days = (52 weeks + 2 days) So,  1 leap year has  2

Rules For Filling Electrons In Orbitals Notes For NCERT Chemistry Class 11

Rules For Filling Electrons In Orbitals Notes For NCERT Chemistry Class 11 For L- orbit,  n  = 2,  l  can have two values (= 0 and 1 which corresponds to s and p sub shells respectively),  m  will have three values (=-1, 0, +1) which corresponds to three orbitals of p sub shell and  s  can have two values +1/2 or -1/2. From this information, following combination will be obtained: n  = 2;  l  = 0;  m  = 0;  s  = +1/2 n  = 2;  l  = 0;  m  = 0;  s  = -1/2 n  = 2;  l  = 1;  m  = -1;  s  = +1/2 n  = 2;  l  = 1;  m  = 0;  s  = +1/2 n  = 2;  l  = 1;  m  =+1;  s  = +1/2 n  = 2;  l  = 1;  m  = -1;  s  = -1/2 n  = 2;  l  = 1;  m  = 0;  s  = -1/2 n  = 2;  l  = 1;  m  =+1;  s  = -1/2 Therefore, L orbit where  n  = 2 can accommodate total of  eight  electrons,  two  in s sub shell and  six  in p sub shell. Likewise, the M orbit with  n  = 3 can accommodate  18 electrons; 2 in s sub shell ( l  = 0), 6 in p sub shell ( l = 1) and 10 in d sub shell ( l = 2). As we pass from on

Common Human Diseases Caused By Protozoa - Biology Notes for Class 12

Common Human Diseases Caused By Protozoa - Biology Notes for Class 12 The disease ( malaria)  is most commonly transmitted by an infected female Anopheles mosquito. The mosquito bite introduces the parasites from the mosquito’s saliva into a person’s blood. The parasites travel to the liver where they mature and reproduce. The parasites initially multiply in liver but later they enter Red Blood Celle (RBC) causing the rupture of cells. Ruptured RBC releases a toxic substance called hemozoin, which causes chill and fever after every 3-4 days. When the female Anopheles mosquito bites the infected person, these parasites enter the body of the mosquito and undergo further development. They multiply to form sporozoites which are stored in the mosquito’s salivary glands. When this mosquito bites another healthy person, the sporozoites are released into his or her body and again the life cycle begins causing the disease. Most deaths are caused by P. falciparum. P. vivax, P. ovale, and

General Awareness Distribution Of Population for SBI/IBPS PO , Clerk & Other Banking Exam

SBI/IBPS PO & Clerk Exam –  General Awareness Distribution Of Population More than 90% of the world’s population lives in 10% of the land surface. Many more people live in the northern hemisphere than in the southern hemisphere. 60% of the world’s population lives in just 10 countries. Out of every 100 people in the world: 61 people live in Asia, 12 people live in Europe, 13 people live in Africa, 8 people live in central and South America, 5 people live in northern America and 1 people live in Oceania (Australia, New Zealand, and Pacific Islands). Daily, weekly and monthly  current affairs  are available, register with us to avail this benefit. Learn complete  General Awareness Distribution Of Population  ...... Takshila Learning offers Online/Offline coaching for SBI/IBPS PO & Clerk exam. We provide complete study material, video lectures, mock test papers, online test series, doubt sessions, webinar and much more for  IBPS Clerk Online clas

Internet Marketing Course - IT WORKED FOR OTHERS LET’S MAKE IT WORK FOR YOU

Internet Marketing Course - IT WORKED FOR OTHERS LET’S MAKE IT WORK FOR YOU “Marketing any product or service online through various mediums such as Social Media, Ad Campaigns and much more“ There are many other ways in which it can be defined many other targets which define  digital marketing  according to their needs and requirements. Depending upon the nature of the business marketing is to be done. As if nature of the business is blogging then the whole and sole motive are to bring traffic to the website so that the person is able to get the information which is being provided through the blogs. Now in a similar way if the nature of the business is an e-commerce website or store then the goal is to sell the products online through digital marketing. Similarly it goes for any grocery store owner he/she wants that people should be able to come from different regions so as to purchase their special products and get free hamper bags with now this offer will be known to limit

Class 11 Maths NCERT Online Solutions - Binomial Theorem

Class 11 Maths NCERT Online Solutions - Binomial Theorem Ques.  If P (n) denotes 2 n > n–1, write P (1), P (k) and P (k+1), where k ∈ N. Solution:  Replacing n by 1, k and k + 1, respectively in P (n), We get P (1) : 2 1 > 2 – 1, i.e., 2 > 1 P (k) : 2 k > k – 1 P (k + 1) : 2 k+1 > (k + 1) – 1, i.e., 2 k+1 > k Ques.  If P (n) is the statement ‘1 + 4 + 7 + (3n – 2) = n(3n − 1)/2 Write P (1), P(k) and P(k + 1). Solution:  To write P(1), the terms on the left-hand side (LHS) of P(n) continue till 3× 1 – 2, i.e., 1. So, P (1) will have only one term in its LHS, i.e., the first term. Also, the right hand side (RHS) of P(1) = 1*(3*1-1) / 2 = 1 Therefore, P (1) is 1 = 1. Replacing n by 2, we get P(2) : 1 + 4 = 2*(3*2-1) / 2 i.e., 5 = 5. Replacing n by k and k + 1, respectively, we get P(k) : 1 + 4 + 7 + …. + (3k – 2) =  k(3k – 1) / 2 P(k + 1) : 1 + 4 + 7 + …. + (3k – 2) + [3 (k + 1) – 2] =(k+1)[3(k+1)-1] / 2 i.e. , 1 + 4 + 7 +…

Important terms related to the Law relating to Transfer of Property Act

CS Executive – Industrial, Labour & General Law  : Important terms related to the Law relating to Transfer of Property Act CS Executive online classes : Vested and Contingent Interest Vested Interest means an interest which is created in favor of a person – without specifying the time when it is to take effect, or specifying it is to take effect on an immediate basis, or on the happening of an event. Contingent Interest means an interest created in favor of a person – to take effect only on the happening or not happening of a specified uncertain event, which may or may not happen. In simple terms, as per the Transfer of Property Act; when an interest is vested, the transfer is complete but when the interest is contingent, the transfer depends on a precedent condition i.e. when the condition s fulfilled the transfer takes place and the interest becomes vested. Vested interest is not defeated by the death of transferee before he obtains possession whereas the Continge

Quantitative aptitude for competitive exams – MIXTURE AND ALLIGATION Part 2: SUCCESSIVE REPLACEMENT:

Quantitative aptitude for competitive exams –  MIXTURE AND ALLIGATION Part 2 : SUCCESSIVE REPLACEMENT: Consider an example to understand the concept of successive replacement. If a vessel has  x litres  of milk and  y litre  of milk is removed from it and replaced with  y litres  of water the milk left in the vessel after the replacement is  (x-y)  litres and the total milk water solution available in the vessel is again  x litres   (x – y +y) . so, after the replacement the proportion of milk in the milk water solution will be equal to: Some examples:- From a solution containing milk and water in the ratio 3 : 4, 10 L is removed and replaced by water. If the resultant solution contains milk and water in the ratio 1 : 2 then what was the amount of the original solution? Solution: Here also we are replacing with water.  So FC and IC must be milk concentrations. Initial concentration of the milk = 3/7 Final concentration of the milk = 1/3 Applying formula 1/3=3/7×(1−10/V)