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Online Notes for 9th Class Science – Animal Tissue – Muscular Tissue

 Online Notes for 9th Class Science – Animal Tissue – Muscular Tissue Class 9 Science notes :  a) Striated muscle : They are called as  striped or skeletal or voluntary. The entire muscle show alternate dark and light strips and therefore called stripped muscle. They are attached to bones and are responsible for body movement, and therefore called  skeletal muscles. These muscles work according to our will, they are called as  voluntary muscles. Striated muscles fibers are long or elongated, unbranched, have many nuclei.Each muscle cell is enclosed in a thin but distinct plasma membrane called sarcolemma.These muscles are present in limbs,face,neck,tongue,pharynx,diaphragm. It helps in smooth contraction and movement. b) Smooth muscle They occur as a bundle or sheets of spindle-shaped cells.They have a single centrally located nucleus in the center of cytoplasm. Delicate, contractile thread called myofibrils run longitudinally through the cell.They are found in walls of the

Quantitative aptitude for Bank PO / Clerk Preparation – SURDS & INDICES

Quantitative aptitude for Bank PO / Clerk Preparation – SURDS & INDICES Baking Online Classes  : Surds & Indices  is one of the important chapters from which you can expect questions in banking as well as SSC level exams. The concept of surds & indices is very easy but you have to practice as much as questions you can so that you can solve the problems in the exams easily. Laws of Indices: a m  x  a n  =  a m  +  n a m  / a n  = a m-n ( a m ) n  =  a mn ( ab ) n  =  a n b n (a/b) n  = a n  / b n a 0  = 1 Surds: Let  a  be a rational number and  n  be a positive integer such that  a (1/n)  = , then =  a (1/n) = /b = () n = a Ques: 1 (15) 3.5 x (15) ? = 15 8 Sol:  Let (15) 3.5 x (15) x = 15 8 . Then, (15) 3.5 +  x = 15 8 . So, 3.5 +  x  = 8 x= (8 – 3.5) x = 4.5 Learn more  Quantitative aptitude for Bank PO / Clerk Preparation – SURDS & INDICES here...... For more topics, video lectures, Online classes for Bank Preparation ,   SB

12th Physics Online Notes Conductor and Insulators

12th Physics Online Notes Conductor and Insulators  CONDUCTORS : Conductors are the device having a conductivity greater than 10 3  s/cm. Basically, electrical properties of any material depend on electronic population inside an atom as conduction is the result of the motion of electrons within the bands. In case of conductors, the conduction band is almost full and conduction band overlaps with valence band hence there us full conduction or full flow of electron from one band to another. Even at low temperature, it results in higher conductivity. For more notes for Class 12 Physics visit  www.takshilalearning.com . SEMICONDUCTORS : Semiconductors have conductivity for silicon (it can range from 10 -5 S/cm to 10 3 S/cm). Their conduction is almost empty and valence band is almost full, the energy gap between the conduction band and valence band is around 1eV. Their no such elements like semiconductors occurs naturally they are formed by doping in insulators. At the high

Online Maths NCERT Solutions Class 11 - Trigonometry

Online Maths NCERT Solutions Class 11 - Trigonometry Trigonometry is most simply associated with planar right-angle triangles (each of which is a two-dimensional triangle with one angle equal to 90 degrees). The applicability to non-right-angle triangles exists, but, since any non-right-angle triangle (on a flat plane) can be bisected to create two right-angle triangles, most problems can be reduced to calculations on right-angle triangles. Thus the majority of applications relate to right-angle triangles. One exception to this is spherical trigonometry, the study of triangles on spheres, surfaces of constant positive curvature, in elliptic geometry (a fundamental part of astronomy and navigation). Trigonometry on surfaces of negative curvature is part of hyperbolic geometry. Read complete chapter click  Maths NCERT Solutions Class 11  Visit our  Maths section  for Class 11 Maths NCERT Solutions. You can get various study modules for better preparation of 11th Class Maths,

Reading Comprehension Questions for Competitive Exams

Reading Comprehension Questions for Competitive Exams Reading comprehension  is one of the most important parts of every exam where verbal is included. In this, you can score good marks just by following these easy tips given below: Sample Passage 1 What Methods Do Andean Farmers Use? Public debate around climate change and its effects on agriculture tend to focus on the large-scale industrial farms of the North. Farmers who work on a small scale and use traditional methods have largely been ignored. However, as the world slowly comes to terms with the threat of climate change, Native farming traditions will warrant greater attention. In the industrial model of agriculture, one or two crop varieties are grown over vast areas. Instead of trying to use local resources of soil and water optimally and sustainably, the natural environment is all but ignored and uniform growing conditions are fabricated through large-scale irrigation and the intensive use of artif

Solved examples of Data Interpretation

IBPS, SBI PO/Clerk exams – Solved examples of Data Interpretation Online banking classes  :-   Data Interpretation  – When you are preparing for Bank PO/Clerk or insurance exam, Data Interpretation is an important topic as 10-15 questions are asked from this topic in the Preliminary examination & also there is a separate section of Data Interpretation in Mains examination of PO level exams. So, you can understand the importance of this topic. So, we at Takshila Learning are providing you DI sets of Pre level that will help you crack the exam. Directions for Questions 1 to 6:  The price and sales information of 3 products of a company, for five years, are given below: Year Product A Price(Rs)        Sales(in’00) Product B Price(Rs)      Sales(in’00) Product C Price(Rs)      Sales(in’00 ) 2000      25                      16      32                   20      52                  40 2001      28                      17      35                   36      50      

Maths NCERT Solutions Class 11 - Permutation

Maths NCERT Solutions Class 11 - Permutation Class 11 maths: - Example:  A family goes to a studio to have their photo taken, and the photographer must arrange them to get the best shot. Three of them have red shirts, four of them have blue shirts, and two of them have black shirts. How many ways can the photographer arrange the family members? In this example, there are 9 family members total, regardless of shirt color, so the  n  value is 9. In the denominator the 3 family members wearing red would be the  n1  value, the 4 family members wearing blue would be the  n2  value, and the 2 family members wearing black shirts would be the  n3  value. P=9! / 3! *4! *2! In the numerator, 9 factorial is 362,880 in the numerator, and 3! 4! and 5! multiplied together in the denominator equal 288. P = 9! / 3! *4! *2! = 9*8*7*6*5*4*3*2*1/3*2*1*4*3*2*1*2*1. Simplify the fraction by dividing. There are 1,260 ways to arrange the nine family members by shirt color. Exampl