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Quantitative aptitude for competitive exams – MIXTURE AND ALLIGATION Part 2: SUCCESSIVE REPLACEMENT:

Quantitative aptitude for competitive exams –  MIXTURE AND ALLIGATION Part 2: SUCCESSIVE REPLACEMENT:

Consider an example to understand the concept of successive replacement.
If a vessel has x litres of milk and y litre of milk is removed from it and replaced with y litres of water the milk left in the vessel after the replacement is (x-y) litres and the total milk water solution available in the vessel is again x litres (x – y +y). so, after the replacement the proportion of milk in the milk water solution will be equal to:
Some examples:-
  1. From a solution containing milk and water in the ratio 3 : 4, 10 L is removed and replaced by water. If the resultant solution contains milk and water in the ratio 1 : 2 then what was the amount of the original solution?
    Solution:
    Here also we are replacing with water.  So FC and IC must be milk concentrations.
    Initial concentration of the milk = 3/7
    Final concentration of the milk = 1/3
    Applying formula
    1/3=3/7×(1−10/V)1
    ⇒7/9=1−10/V
    ⇒2/9=10V
    ⇒V=45

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